3D interpolation#

Interpolation of a three-dimensional regular grid.

Trivariate#

The trivariate interpolation allows obtaining values at arbitrary points in a 3D space of a function defined on a grid.

This method performs a bilinear interpolation in 2D space by considering the axes of longitude and latitude of the grid, then performs a linear interpolation in the third dimension. Its interface is similar to the bivariate class except for a third axis, which is handled by this object.

Note

When using a time axis, care must be taken to use the same unit of dates, between the axis defined and the dates supplied during interpolation. The function pyinterp.TemporalAxis.safe_cast() automates this task and will warn you if there is an inconsistency during the date conversion.

import cartopy.crs
import matplotlib
import matplotlib.pyplot
import numpy

import pyinterp
import pyinterp.backends.xarray
import pyinterp.tests

The first step is to load the data into memory and create the interpolator object:

ds = pyinterp.tests.load_grid3d()
interpolator = pyinterp.backends.xarray.Grid3D(ds.tcw)

We will build a new grid that will be used to build a new interpolated grid.

Note

The coordinates used for interpolation are shifted to avoid using the points of the trivariate function.

Warning

When using a time axis, care must be taken to use the same unit of dates, between the axis defined and the dates supplied during interpolation. The function pyinterp.TemporalAxis.safe_cast() automates this task and will warn you if there is an inconsistency during the date conversion.

mx, my, mz = numpy.meshgrid(numpy.arange(-180, 180, 0.25) + 1 / 3.0,
                            numpy.arange(-80, 80, 0.25) + 1 / 3.0,
                            numpy.array(['2002-07-02T15:00:00'],
                                        dtype='datetime64'),
                            indexing='ij')

We interpolate our grid using a classical:

trivariate = interpolator.trivariate(
    dict(longitude=mx.ravel(), latitude=my.ravel(), time=mz.ravel()))

Bicubic on 3D grid#

Used grid organizes the latitudes in descending order. We ask our constructor to flip this axis in order to correctly evaluate the bicubic interpolation from this 3D cube (only necessary to perform a bicubic interpolation).

interpolator = pyinterp.backends.xarray.Grid3D(ds.data_vars['tcw'],
                                               increasing_axes=True)

We interpolate our grid using a bicubic interpolation in space followed by a linear interpolation in the temporal axis:

bicubic = interpolator.bicubic(
    dict(longitude=mx.ravel(), latitude=my.ravel(), time=mz.ravel()))

We transform our result cubes into a matrix.

trivariate = trivariate.reshape(mx.shape).squeeze(axis=2)
bicubic = bicubic.reshape(mx.shape).squeeze(axis=2)
lons = mx[:, 0].squeeze()
lats = my[0, :].squeeze()

Let’s visualize our results.

fig = matplotlib.pyplot.figure(figsize=(5, 8))
ax1 = fig.add_subplot(
    211, projection=cartopy.crs.PlateCarree(central_longitude=180))
pcm = ax1.pcolormesh(lons,
                     lats,
                     trivariate.T,
                     cmap='jet',
                     shading='auto',
                     transform=cartopy.crs.PlateCarree(),
                     vmin=0,
                     vmax=80)
ax1.coastlines()
ax1.set_extent([80, 170, -45, 30], crs=cartopy.crs.PlateCarree())
ax1.set_title('Trilinear')

ax2 = fig.add_subplot(
    212, projection=cartopy.crs.PlateCarree(central_longitude=180))
pcm = ax2.pcolormesh(lons,
                     lats,
                     bicubic.T,
                     cmap='jet',
                     shading='auto',
                     transform=cartopy.crs.PlateCarree(),
                     vmin=0,
                     vmax=80)
ax2.coastlines()
ax2.set_extent([80, 170, -45, 30], crs=cartopy.crs.PlateCarree())
ax2.set_title('Spline & Linear in time')
fig.colorbar(pcm, ax=[ax1, ax2], shrink=0.8)
fig.show()
Trilinear, Spline & Linear in time

Total running time of the script: (0 minutes 12.609 seconds)

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